Education of Women and Girls Research Paper Example | Topics and Well Written Essays - 2250 words

Education of Women and Girls - Research Paper Example From the discussion it is clear that  80 percent of out-of-school girls in Yemen and 62 percent in Pakistan are unlikely even to enter school, compared with 36 percent of boys in Yemen and 27 percent in Pakistan. The situation is the most dramatic in sub-Saharan Africa, where 12 million girls are unlikely to enroll. In 2007, eighteen sub-Saharan countries had the gender parity index (GPI) of less than 0,90, which meant that they had not achieved the goal of gender parity in primary schooling, set by UNESCO for 2005.  This paper discusses that  there is a strong inverse relation between gender parity and school enrolment; in poor countries with a low enrolment ratio there is usually a large disparity between boys and girls out-of-school. Thus, several developing countries have included strategies to reach gender parity as part of their wider policies aimed to provide all children with universal primary education. The policy measures introduced in Yemen to increase the gender par ity index contributed significantly to the increase in enrolment from 2.3 million in 1999 to 3.2 million in 2005. The interventions targeted at out-of-school girls, such as providing girls in grades 1 to 6 with free textbooks and employing more female teachers in rural areas, enabled many girls to enroll, which lead to an increased number of all school children. Due to security concerns and household labor demands, few parents decide to enroll their daughters in schools far away from home.

Calculus II - Integration and Statistics Term Paper

Calculus II - Integration and Statistics - Term Paper Example Task A: This task requires the creation of a real-world science question/problem that requires the application of differentiation for it to be solved by the carrying out the following tasks: 1. A description in the context of the above real-world problem of the following terms using appropriate units. a) Independent variable b) Dependent variable c) Range d) Domain 2. An explanation of what the real-world problem above is about or is addressing 3. The problem created should involve taking the second and the first derivative of the above problem which includes the following components: a) Describe how f’(x) describes the behavior of f(x) within the context of the real-world application. b) Describe how f’’(x) describes the characteristics and changes of f(x) and f’(x) in the context of the real-world application. 4. Provide an answer that comprises of all relevant mathematical justifications for each step in the real-world solution context. Question A jet f ollows a path with distance in km, which is given by: Given that the horizontal velocity is expressed as V(x) = x, find the direction and magnitude of the velocity when the jet hits the ground if time taken is in minutes. The assumption made here is such that the terrain is all level (Bourne, 2011). Solution Let us first see a graph of the motion, to clarify what is going on. It can be seen that the jet hits the ground again somewhere around x = 9.5 km. At this point, the horizontal velocity is positive (the jet is from going left to right) and the vertical velocity is negative (the jet is going down). "V(x) = x" means that as x increases, the horizontal velocity also increases with the same number (different units, of course). So for example, at x = 2 km, the horizontal speed is 2 km/min, and at x = 7 km, the horizontal speed is 7 km/min, and so on. To calculate the magnitude of the velocity as the jet hits the ground, it is important that we know the vertical and horizontal aspect s of the velocity at this instance. (1) Horizontal velocity. In order to find the exact point the rocket hits the ground, it is necessary to find a solution for the following equation we only need to solve the following: Factorizing gives: And solving for 0 gives us x = 0, x = -3v10, x = 3v10 We only need the last value, x = 3v10 ? 9.4868 km (This value is consistent with the graph above). So the horizontal speed when the rocket hits the ground is 9.4868 km/min (since V(x) = x). (2) Vertical velocity. We now need to use implicit differentiation with respect to t (not x!) to find the vertical velocity. However, we already know dx/dt and x at impact, so we simply substitute: This gives us a negative velocity, as we expected before: So now, we need to calculate the magnitude of the velocity. This considers both the horizontal and vertical components. Magnitude = Substituting, we have: Velocity has magnitude and direction. Now for part of the direction. Angle of motion: Substituting our vertical and horizontal components, we have: In degrees, this is equivalent to -1.107148718 ? 57.25578 = -63.3907Â ° We can see that this answer is reasonable by zooming in on that part of the graph where the jet hits the ground (with equal-axis scaling): Therefore, in summary, the velocity of the jet when it hits the ground is 21.2 km/min in the direction 63.4